11. April shoots an arrow upward at a speed of 80 feet per second from a platform 25 feet high. The pathway

11. April shoots an arrow upward at a speed

of 80 feet per second from a platform 25
feet high. The pathway of the arrow can
be represented by the equation h =-
16t2 + 80t + 25, where h is the height
and t is the time in seconds. What is the
maximum height of the arrow? [3]

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